/ Can you answer this question?

This topic has been archived, and won't accept reply postings.
So this is my question that I am seriously confused/ stuck on. I think I have the answer but not sure.

If the temperature at 194m above sea level is 8 C and you were at 995m on a very wet and windy day, with a wind speed of 10km per hour, what wind chill temperature would you expect? (Please show your calculations)

Expecting that it is wet therefore be cloudy my calculations would be as follows:
995 – 194 = 801
801 / 200 = 4.005
Knowing that on a cloudy day air temp. cools at -1 for every 200 metres.
-1 x 4.005 = - 4.005
8 - -4.005 = 3.995 C
Temperature at 995m = 3.995 C

What do you think, some clarification please.
In reply to themountaintamer: I think you are being much too simplistic, thare are no hard and fast values for the variations. When we were on Everest West Face in 1988 the lead team were pushing out the route in temps which the wind chill calculations gave as -90C. They were functioning as normally as could be expected in ordinary down clothing, I have to seriously doubt it was -90C, though maybe they were just supermen, they were SAS after all
In reply to themountaintamer: just doing a rough guesstimate, I also arrive at 4c(ish) but do you not now have to factor in the airspeed to get the windchill temp?
In reply to aultguish: Thats also what I thought but cant find or figure out how to do that. Been staring at my books and the internet to find out but struggling. Cheers