In reply to Wonko The Sane:
> I deserve that for being pedantic myself. But no, it is not a 'blue photon' it is simply a photon at a specific frequency. It's 'blueness' is just something we perceive.
It's getting philosophical now. If a gajillion blue-range photons are blue, then what about half that number? And half that? And so on...
Also there are biological entities in nature that can detect single photons. Do they see blue or not?
Anyway, I take your point.
> Lol, again, I deserve this. I was trying to keep it simple.
> No, they do not have 'size' as such. And I do not claim to understand it fully. They do have a volume of sorts.
Not sure about volume. I'm not an expert in this, but the only physical length quantity possessed by propogating light that I know of is the wavelength.
>It is not certain one way or the other whether they have mass.
I think the correct statement is that photons have zero rest mass, but they have momentum and hence they have mass-energy: we know from Einstein that energy is a contribution from rest mass plus kinetic energy. Actually you can't see this from E=mc^2, you have to use Einstein's full version that holds for masslass particles, which I think (without Googling) is
E^2=m^2c^4+p^2c^2 (?)
> I do not pretend to understand WHY light is affected by gravity if they don't have mass. I'm sure I was taught some explanation of it years ago, but it was over 20 years ago!
Nowadays, gravity is understood to be the bending of space-time by mass-energy (which includes light!), and light follows the shortest path through this curved space. It therefore appears to be bent by massive bodies, like stars.
But I think we were talking in the context of Newtonian mechanics?
Start with Newton's second law: F=ma, where m is the mass of the object A. Let B be some large gravitating object of mass M and write down the force from Newton's law of gravitation:
F = mMG/r^2
where r is the distance between A and B, G is Newton's constant. Put both sides together
ma = mMG/r^2
cancel the m
a = MG/r^2
and you get an equation for acceleration that is independent of m. so it makes sense also when m=0. So the equation for massless particles is the same as the equation for massive ones.