In reply to Fiend:
Okay, let's calculate the relative effects of the gravitational attraction of earth and moon on a mass on the earth's surface, using Newton's law of gravitational attraction:
F = (G * m1 * m2)/d^2
i.e. the force if proportional to the mass, and inversely proportional to the square of the distance. G is the universal gravitational constant, m1 and m2 are the masses, and d is the distance between centres of mass.
So, let's take a fat punter, say, m1 = 100 kg.
For the earth,
m2 = 6.0e24 kg
d = 6.4e6 m (radius of the earth)
Fe = 981 N
(not surprising, since we know that F = ma, where a in this case is the acceleration due to gravity, or g = 9.81m/s^2)
for the moon
m2 = 7.3e22 kg
d = 3.9e8 m (distance from earth to moon)
Fm = 0.0032 N
So, the ratio of lunar to terrestrial forces is
Fm/Fe
= 0.0032/981
i.e. 0.00033%
So, no, you don't get 'low gravity' days because of the moon.
Now go and look at:
http://www.npl.co.uk/mass/faqs/gravity.html
for some interesting comments about gravity, latitude and altitude...
or try the questions at:
http://www.emanuel.org.uk/curriculum/science/physics/website/alevel/aprobs/...